An oblique candle with a volume of 270 cubic centimeters is 18 centimeters tall. The width of the triangular candle base is 5 centimeters, and the width of the slanted candle is 7 centimeters
Volume of the candle:
V = B h ( where B is the base area and h is the height )
270 = B 18
B = 270 : 18
B = 15 cm²
B = a b / 2
B = 5 b / 2
15 = 2.5 b
b = 15 : 2.5
b = 6 cm
Therefore dimensions of the box are: a = 7cm, b = 6 cm, c = 18 cm.
Answer: B ) 7 by 6 by 18 cm.
The height of the triangular base of the oblique candle with a base of 5cm comes to be 6cm.
The volume of a prism is the product of the area of the base and height.
Given that volume of the candle=270 cubic centimetres
Volume = Area of the base * height
\(270=A_{base} *18\)
\(A_{base} =15\)
Since the base is triangular in shape,
So, \(15=\frac{1}{2} *5*h'\)
\(h'=6\)
So, the height of the triangular base =6cm
Thus, the height of the triangular base of the candle comes to be 6cm.
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