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levya31
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In a large group of Americans in 2001-2002, the probability of visiting the emergency room once in the past 12 months was 0.14, and the probability of visiting twice was 0.04.

AWhat was the probability of visiting the emergency room one or two times?
BFor two randomly chosen Americans in 2001-2002, what is the approximate probability that both visited the emergency room exactly once? (Round your answer to two decimal places.)
CExplain why we cannot solve for the probability that two people chosen from the same household both visited the emergency room exactly once.

Verified Answer :

nobillionaireNobley

a.) Let A be the event of the emergency room once and B be the event of visiting the emegency room twice, then
P(A or B) = P(A) + P(B) = 0.14 + 0.04 = 0.18
Therefore, the probability of visiting the emergency room one or two times is 0.18


b) P(A) and P(A) = 0.14 x 0.14 = 0.0196
Therefore, for
two randomly chosen Americans in 2001-2002, the approximate
probability that both visited the emergency room exactly once is 0.0196

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