how do you solve this equation 3^3x-7=81^12-3x
I think you meant...3^(3x-7)=81^(12-3x) (note that 81=3^4) so3^(3x-7)=3^4^(12-3x)3^(3x-7)=3^(48-12x) taking log or natural log of both sides show that3x-7=48-12x15x=55x=11/3
