Answer:
The correct option is 1.
Step-by-step explanation:
The given equation is
\(6x^2+2x-8=0\)
Taking out the common factor.
\(2(3x^2+x-4)=0\)
Middle term can be written as 4x-3x, to find the factored form of the given equation.
\(2(3x^2+4x-3x-4)=0\)
\(2(x(3x+4)-(3x+4))=0\)
\(2(3x+4)(x-1)=0\)
The factored form of the given equation is 2(3x+4)(x-1)=0. Therefore the correct option is 1.
