Answer : The force of interaction between them is 1.35 N
Explanation :
Charge 1 \(q_1=7.1\times 10^{-6}\ C\)
Charge 2, \(q_2=6.9\times 10^{-6}\ C\)
Distance between charges, \(d=5.7\times 10^{-1}\ m\)
The force of interaction between them is given by using Coulomb's law. It is written as :
\(F=k\dfrac{q_1q_2}{d^2}\)
k is electrostatic constant
\(F=9\times 10^9\times \dfrac{7.1\times 10^{-6}\ C\times 6.9\times 10^{-6}\ C}{(5.7\times 10^{-1}\ m)^2}\)
\(F=1.35\ N\)
Hence, this is the required solution.
