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The sum of the polynomials 6x3 + 8x2 – 2x + 4 and 10x3 + x2 + 11x + 9 is 16x^3 + 9x^2 + 13x + 13 16x^3 + 9x^2 + 9x + 13 16x^3 + 7x^2 - 9x + 13 . Adding 3x – 2 to this sum gives a sum of 16x^3 + 9x^2 + 16x + 15 16x^3 + 9x^2 + 12x + 11 16x^3 + 9x^2 – 7x + 15 .

Verified Answer :

Answer:

\(16x^{3} +9x^{2} +9x+13\)

\(16x^{3} +9x^{2} +12x+11\)

Step-by-step explanation:

We are given two polynomials:

\(6x^{3} +8x^{2} -2x+4\)   and \(10x^{3} +x^{2}+11x+9\)

Add these polynomials

\(6x^{3} +8x^{2} -2x+4+10x^{3} +x^{2}+11x+9\)

\(16x^{3} +9x^{2} +9x+13\)

Thus Option B of part a  is correct

Now we are asked to add 3x-2 to this result :

\(16x^{3} +9x^{2} +9x+13+3x-2\)

\(16x^{3} +9x^{2} +12x+11\)

Thus the answer is \(16x^{3} +9x^{2} +12x+11\)

Hence option B of part b is correct