The coordinates of the vertices of triangle ABC are given in the table. A B C (4,2) (6,7) (13,1) Triangle ABC is reflected across y=−x . What are the vertices of triangle A'B'C'? Enter your answers in the boxes. A': ( , ) B': ( , ) C': ( , )
Answer:
A'(-2, -4)
B'(-7, -6)
C'(-1, -13)
Step-by-step explanation:
The rule of reflection across y = -x is given by:
\((x, y) \rightarrow (-y, -x)\)
As per the statement:
The coordinates of the vertices of triangle ABC are given:
A(4, 2), B(6, 7) and C(13, 1)
Apply the rule of reflection y = -x to triangle ABC:
\(A(4, 2) \rightarrow A'(-2, -4)\)
\(B(6, 7) \rightarrow B'(-7, -6)\)
\(C(13, 1) \rightarrow C'(-1, -13)\)
Therefore, the vertices of triangle A'B'C are:
A'(-2, -4)
B'(-7, -6)
C'(-1, -13)