Answer:
The salt is in the water be 3 lb.
Step-by-step explanation:
Formula
\(Percentage = \frac{Part\ value\times 100}{Total\ value}\)
As given
Twenty pounds of a salt-water solution contains fifteen percent salt.
Let us assume that the salt is in the water be x.
Percentage = 15%
Total value = 20 pounds
Put in the formula
\(15= \frac{x\times 100}{20}\)
\(x = \frac{15\times 20}{100}\)
\(x = \frac{300}{100}\)
x = 3 pounds
or
x = 3 lb
Therefore the salt is in the water be 3 lb.
