Answer: The chemical formula for the compound will be \(CaI_2\)
Explanation:
Calcium is the 20th element of the periodic table having electronic configuration of \([Ar]4s^2\)
This element will loose 2 electrons and thus shows an oxidation state of +2 units.
Iodine is the 53rd element of the periodic table having electronic configuration of \([Kr]5s^24d^{10}5p^5\)
This element requires 1 electron and thus shows an oxidation state of -1 units.
So, by criss-cross method, the oxidation state of the ions will get exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
Hence, the chemical formula for the compound formed will be \(CaI_2\)
