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A circular swimming pool has a radius of 15 ft. There is a path all around that pool that is three feet wide.




What is the circumference of the outer edge of the path around the pool? Use 3.14 for Pi.

Verified Answer :

Answer:

Circumference(C) of the circle is given by:

\(C = 2 \pi r\)

where, r is the radius of the circle.

As per the statement:

A circular swimming pool has a radius of 15 ft.

⇒radius of the pool(r) = 15 ft

There is a path all around that pool that is three feet wide.

⇒radius of the outer edge of the path around the pool(r') = 15 +3 = 18 ft

Substitute these in the formula we have;

\(C = 2 \pi r'\)

⇒\(C = 2 \cdot 3.14 \cdot 18 = 113.04 ft\)

Therefore, the circumference of the outer edge of the path around the pool is, 113.04 ft

The circumference of the outer edge of the path around the pool is; 113.04 ft

How to calculate the circumference of a Circle

We are given;

Radius of inner circle; r = 15 ft

Since there is an external path of 3 ft wide, then radius of new circle created by path is;

R = 15 + 3 = 18 ft

Formula for circumference of a circle is;

C = 2πR

Thus;

Circumference of the outer edge is;

C = 2π × 18

C = 2 3.14 18

C = 113.05 ft

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