A cup falls off of a table from a height of 0.75 m. What is the impact speed of the cup?
Answer:
The impact speed of the cup is 3.83 m/s.
Explanation:
Given that,
Height = 0.75 m
We need to calculate the impact speed of the cup
Using kinetic and potential energy
\(K.E=P.E\)
\(\dfrac{1}{2}mv^2=mgh\)
Where,
M = mass of the cup
v = velocity of cup
g = acceleration due to gravity
h = height
Put the value into the formula
\(\dfrac{1}{2}v^2=gh\)
\(v=\sqrt{2gh}\)
\(v=\sqrt{2\times9.8\times0.75}\)
\(v=3.83\ m/s\)
Hence, The impact speed of the cup is 3.83 m/s.