Answer : The correct option is, 2880 J
Solution :
According to the question,
K.E + Energy lose to friction = P.E
\(\text{Energy lose to friction}=P.E-K.E\\\\\text{Energy lose to friction}=mgh-\frac{1}{2}mv^2=m(gh-\frac{1}{2}v^2)\)
where,
m = mass of object = 60 Kg
g = acceleration due to gravity = \(9.8m/s^2\)
h = height = 10 m
v = velocity of an object = 10 m/s
Now put all the given values in the above formula, we get the energy lost to friction.
\(\text{Energy lose to friction}=60Kg\times (9.8m/s^2\times 10m-\frac{1}{2}\times (10m/s)^2)=2880\text{ Kg }m^2/s^2=2880J\)
Therefore, the amount of energy she lose to friction is, 2880 J
