solve the system of equations below:
5x-2y=18
3x+3y=15
Answer : The value of x and y is, 4 and 1 respectively.
Step-by-step explanation :
The given equations are:
\(5x-2y=18\) ..........(1)
\(3x+3y=15\) ..........(2)
Using substitution method,
\(5x-2y=18\)
\(5x=18+2y\)
\(x=\frac{18+2y}{5}\) ...........(3)
Now putting equation 3 in 2, we get the value of y.
\(3x+3y=15\)
\(3(\frac{18+2y}{5})+3y=15\)
\((\frac{54+6y}{5})+3y=15\)
\(54+6y+15y=75\)
\(6y+15y=75-54\)
\(21y=21\)
\(y=1\)
Now putting value of y in equation 3, we get the value of x.
\(x=\frac{18+2y}{5}\)
\(x=\frac{18+2\times 1}{5}\)
\(x=\frac{18+2}{5}\)
\(x=4\)
Thus, the value of x and y is, 4 and 1 respectively.