Answer:
9 \pi m^2
Step-by-step explanation:
Given that there is a circle whose area is 72pi m^2
Area of a circle = \(\pi r^2 =72\pi\\\)
We are to find the area of a sector with angle 45 degrees
We have formula for area of sector as
Area of sector = central angle* area of circle/360
Substitute the known values to get
Area of sector = \(\frac{45}{360} (72\pi) = 9 \pi m^2\)
Hence we get
area of sector with 45 degrees = \(9 \pi m^2\)
