Answer: The electron structure of \(Be^{2+}\) ion is \(1s^2\)
Explanation: Beryllium is the 4th element of the periodic table.
The electronic configuration of Be-element in its ground state is:
\(Be(Z=4):1s^22s^2\)
For the Beryllium element to have +2 charge, two electrons must be removed from the electronic configuration. So, the electronic configuration for the \(Be^{2+}\) ion is:
\(Be^{2+}:1s^2\)
