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anaguzman

the answer is x=−4/3 or x=1

Answer:

The factored form of the equation  \(6x^{2}+2x-8=0\) is            \(2(3x+4)(x-1)=0\)

Step-by-step explanation:

Given equation is \(6x^{2}+2x-8=0\)

Above equation can be written as

\(6x^{2}+8x-6x-8=0\)

=>\(2x(3x+4)-2(3x+4)=0\)

Taking (3x+4) common from the above equation, we get

\((3x+4)(2x-2)=0\)

Again taking 2 common out of (2x-2) we get

=>\(2(3x+4)(x-1)=0\)

Thus the factored form of the given equation is \(2(3x+4)(x-1)=0\)

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