take the squar root of both sides and remember the positive and negative roots
remember \(\sqrt{ \frac{x}{y} } = \frac{ \sqrt{x} }{ \sqrt{y} }\)
so
\(x^2= \frac{49 }{121 }\)
square root both sides
\(x= \sqrt{ \frac{49}{121} } = \frac{ \sqrt{49} }{ \sqrt{121} }= +/-\frac{ 7 }{ 11 }\)
x=-7/11 or 7/11
