Answer:
p=1
Step-by-step explanation:
We are given that an equation
\(\frac{2}{5}+p=\frac{4}{5}+\frac{3}{5}p\)
We have to find the solution of given linear equation .
Subtraction property of equality
\(p-\frac{3}{5}p+\frac{2}{5}=\frac{4}[5}\)
\(\frac{5p-3p}{5}+\frac{2}{5}=\frac{4}{5}\)
Combine like terms
\(\frac{2}{5}p+\frac{2}{5}=\frac{4}{5}\)
\(\frac{2}{5}p=\frac{4}{5}-\frac{2}{5}\)
Subtraction property of equality
\(\frac{2}{5}p=\frac{2}{5}\)
When a fraction term in multiply goes form one side to other side then the term will be reciprocal.
\(p=\frac{2}{5}\times \frac{5}{2}\)
\(p=1\)
Hence, p=1
