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Kianacornelius7
Kianacornelius7 Kianacornelius7
  • 20-03-2017
  • Mathematics
Answered

Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have altogether?

Verified Answer :

bcalle
bcalle bcalle
  • 20-03-2017

.05n + .10d = 4.85
n - 34 = d
Substitute the second equation into the first equation and solve for n.
.05n + .10(n - 34) = 4.85
.05n + .10n - 3.4 = 4.85
combine like terms
.15n - 3.4 = 4.85
add 3.4 to both sides
.15n = 8.25
divide both sides by .15
n = 55
d = n - 34
d = 55 - 34
d = 21

CHECK
21 .1 = 2.10
55
.05 = 2.75
2.10 + 2.75 = 4.85

21 dimes and 55 nickels

Answer Link
Anonymous Anonymous
  • 15-10-2019

Answer:

Step-by-step explanation:

it would be 76 coins

Answer Link

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