Verified Answer :
Answer:
Height of flag pole to the nearest foot is 43 feet
Step-by-step explanation:
In the diagram we have flag pole AB and C is the point on the ground.
It is given that angle of depression is 30°
and the distance of the point C from the base B is 75 feet
so we have
BC= 75 feet
∠C = 30°
AB= h feet
now in right ΔABC
\(tan C = \frac{opposite \ side }{base} \\tan C=\frac{AB}{BC}\)
now we plug AB= h , ∠C= 30° and BC =75
\(tan 30= \frac{h}{75}\)
\(75 tan30 = h\) ( multiply both sides by 75)
\(h= 75 tan 30 =75 (0.5773)\\ h= 43.3 feet\\\)
Height of flag pole to the nearest foot is
h= 43 feet
Answer:
B) 43 feet
Step-by-step explanation:
Let AB represents the height of pole and C represents the point on the ground ( shown in the below diagram ),
We need to find : Measure of AB.
Since, angle of depression from the top of a flag pole to a point on the ground is 30°,
By the alternative interior angle theorem,
m∠ACB = 30°,
∵ m∠ABC = 90°,
By the trigonometric ratio,
\(\tan 30^{\circ}=\frac{AB}{BC}\)
We have BC = 75 ft,
\(\tan 30^{\circ}=\frac{AB}{75}\)
\(\frac{1}{\sqrt{3}} = \frac{AB}{75}\)
\(\implies AB = \frac{75}{\sqrt{3}}= 43.3012\approx 43\)
Hence, the pole would be 43 ft tall ( approx )