The first thing we must do for this case is to calculate the scale factor.
For this, we make the relationship between two parallel sides.
We have then:
\(k =\frac{B'C'}{BC}
\)
Substituting values we have:
\(k = \frac{9.5}{3.8}
k = 2.5
\)
We are now looking for the value of AB
We have then:
\(AB = \frac{A'B'}{k}
\)
Substituting values:
\(AB = \frac{15}{2.5}
AB = 6
\)
Answer:
The scale factor is:
\(k = 2.5
\)
The value of AB is:
\(AB = 6\)
