Gabriel has these cans of soup in his kitchen cabinet. • 2 cans of tomato soup • 3 cans of chicken soup • 2 cans of cheese soup • 2 cans of potato soup • 1 can of beef soup Gabriel will randomly choose one can of soup. Then he will put it back and randomly choose another can of soup. What is the probability that he will choose a can of tomato soup and then a can of cheese soup? Mathematics

Using the probability concept, it is found that there is a 0.04 = 4% probability that he will choose a can of tomato soup and then a can of cheese soup.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem:

For the first can, there is a total of 2 + 3 + 2 + 2 + 1 = 10 cans, of which 2 are of tomato soup, hence \(P(A) = \frac{2}{10} = 0.2\)

For the second can, there will be also 10, of which 2 are of cheese soup, hence \(P(B) = \frac{2}{10} = 0.2\).

Then, since the cans are independent, the probability of both is the multiplication of each, that is:

\(P(A \cap B) = P(A)P(B) = 0.2(0.2) = 0.04\)

0.04 = 4% probability that he will choose a can of tomato soup and then a can of cheese soup.

You can learn more about the probability concept at https://brainly.com/question/15536019