\(\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta\pi r^2}{360}\qquad
\begin{cases}
\theta=\textit{angle in degrees}\\
r=radius\\
----------\\
A=2.62\\
r=10
\end{cases}\implies 2.62=\cfrac{\theta\cdot \pi \cdot 10^2}{360}\)
\(\bf 2.62=\cfrac{\theta\cdot \pi \cdot 10^2}{360}\implies 2.62\cdot 360=\theta\pi \cdot 100\implies \cfrac{2.62\cdot 360}{100\pi }=\theta\)
