emilybb195 emilybb195

17-03-2017
Mathematics

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Anonymous Anonymous

18-03-2017

\(\dfrac{x}{x-5} ~ \cdot~ \dfrac{2x}{x+4} =\dfrac{x~ \cdot~ 2x}{(x-5)(x+4)}= \dfrac{2x^2}{x^2 -x -20}\)

The answer is D.

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