Answer:
The values of a=2,b=3,c=7.
Step-by-step explanation:
Given : Quadratic equation \(2x^2+3x+7=0\)
To find : Identify the values of a,b and c in the given quadratic equation?
Solution :
The general form of the quadratic equation is \(ax^2+bx+c=0\)
Where, a is the coefficient of \(x^2\)
b is the coefficient of x
c is the constant term.
Now, we compare the given quadratic equation with the general form.
Quadratic equation \(2x^2+3x+7=0\)
Here, a=2 , b=3 , c=7.
Therefore, The values of a=2,b=3,c=7.
