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A spinner with six sections labeled A through F is spun. The probability of spinning a consonant (B, C, D, or F) is 23 . What is the probability of not spinning a consonant? Enter your answer as a fraction, in simplest form, in the box.

Verified Answer :

konrad509

\(1-\dfrac{2}{3}=\dfrac{1}{3}\)

It's 1/3.

JeanaShupp

Answer: \(\frac{1}{3}\)

Step-by-step explanation:

Given: A spinner with six sections labeled A through F is spun.

The probability of spinning a consonant (B, C, D, or F) =\(\frac{2}{3}\)

Then, the probability of not spinning a consonant

= 1 - probability of spinning a consonant

Thus, the probability of not spinning a consonant =\(1-\frac{2}{3}\)

Hence, the probability of not spinning a consonant =\(\frac{1}{3}\)

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