PRESSURE = FORCE/AREA
F1/A1=F2/A2
15,000/10=1,100/A2
A2=1,100/1500=11/15
It is approximately 0.733m^2
The area of the smaller piston is about 0,733 m2
To measure the pressure in a surface, it is necessary to relate the value of the applied force and the size of the area that suffers this force, in such a way that:
\(p = \frac{F}{A}\)
As in a hydraulic platform, the pressure is equal on both sides, the initial pressure must be equal to the final pressure:
\(\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}\)
Applying the values given in the question we have:
\(\frac{15,000}{10} = \frac{1,100}{A_{2}}\)
\(A_{2}=\frac{1,100}{1,500}\)
\({A_{2} = 0,73m^{2}\)
So, the area of the smaller piston if a force of 1,100 N is equal to 0,73m2
Learn more about hydraulic systems in: brainly.com/question/18328907