The equation for the circle is:
x2+y2−12x+6y−19=0
What is the center of the circle?
(-6, 3)
(12, -6)
(6, -3)
(-12, 6)
x2+y2−12x+6y−19=0
What is the center of the circle?
(-6, 3)
(12, -6)
(6, -3)
(-12, 6)
