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Verified Answer :

the correct answer is c.

Answer:

C. (\(\frac{13}{22},\frac{1}{22})\)

Step-by-step explanation:

We are given that a system of equations

\(7x-3y=4\)

\(2x-4y=1\)

We have to find the solution of the system of equation .

Using elimination method,

Multiply first equation by 2 and equation second multiply by 7

Then, we get

\(14x-6y=8\)

\(14x-28y=7\)

Now, subtract equation second from first equation

\(22y=1\)

\(y=\frac{1}{22}\)

Subtract the value of y in equation first

Then, we get

\(7x-3\times \frac{1}{22}=4\)

\(7x-\frac{3}{22}=4\)

\(7x=4+\frac{3}{22}=\frac{91}{22}\)

\(x=\frac{91}{22}\times \frac{1}{7}=\frac{13}{22}\)

Hence, the solution of given system is (\(\frac{13}{22},\frac{1}{22})\)