A runner starts from a rest and speeds up with a constant acceleration . if she has gone a distance of 30 m at the point when she reaches a speed of 8 m/s what is her acceleration
Answer:
\(a = 1.07 m/s^2\)
Explanation:
As we know that the runner starts from rest position
So here we can say
\(v_i = 0\)
now the distance moved by the runner is given as
\(d = 30 m\)
also we know that final speed of the runner will be
\(v_f = 8 m/s\)
now we know that
\(v_f^2 - v_i^2 = 2 a d\)
\(8^2 - 0 = 2(a)(30)\)
\(a = \frac{64}{60}\)
\(a = 1.07 m/s^2\)