A taxi starts from Monument Circle and travels 5 kilometers to the east for 5 minutes. Then it travels 10 kilometers to the south for 10 minutes.

The taxi is moving with reference to

AMonument circle
BThe passengers
CThe taxi driver

For each leg of the trip, the taxi’s

AAverage speed
BAverage velocity
CDirection

stays the same, but its

AAverage speed
BAverage velocity

changes.

The taxi is moving with reference to A) Monument Circle. For each leg of the trip, the taxi's A) Average speed stays the same, but it's B) Average velocity changes.

Answer Link

skyluke89 skyluke89 · Answer 2 · 2018-10-10T05:53:10-04:00

The correct sentence is:

The taxi is moving with reference to A) Monument circle. For each leg of the trip, the taxi’s A) Average speed stays the same, but its B) Average velocity changes.

In fact, speed it is only the ratio between the distance traveled and the time taken - so it does not take into account the direction of motion. The speed in the first leg is

\(v=\frac{5 km}{5 min}=1 km/min\)

while the speed in the second leg is

\(v=\frac{10 km}{10 min}=1 km/min\)

so the speed stays the same.

However, the velocity also takes into account the direction of motion: in the first leg, the direction is east, while in the second leg, the direction is south, therefore the average velocity has changed, since the direction has changed.