N2 + 3H2 ---> 2NH3 We want to produce 2.75 mol of NH3. How many moles of nitrogen would be required?
A5.5 moles
B1.38 moles
C1.83 moles
D4.13 moles
N2 + 3H2 ---> 2NH3 Suppose 6.00 mol of H2 reacted with sufficient nitrogen. How many moles of ammonia would be produced?
A1 mole
B2 moles
C3 moles
D4 moles
A5.5 moles
B1.38 moles
C1.83 moles
D4.13 moles
A1 mole
B2 moles
C3 moles
D4 moles