If 75 g of liquid water ( C = 4.18 j/g C ) in a calorimeter changes temperature from 25 C to 75 C, how much heat was transferred
The answer is 157kJ
formula: q=mcT
q= 75 g x 4.18 J/goC x 50 oC
q= 157 kJ
Answer:
The heat transferred is 157 kJ.
Step-by-step explanation:
Given : If 75 g of liquid water ( C = 4.18 j/g C ) in a calorimeter changes temperature from 25 C to 75 C.
To find: How much heat was transferred ?
Solution :
Using the formula, \(q=mc\triangle T\)
Where,
q - heat absorbed
c - the specific heat of the substance, in your case of water
ΔT - the change in temperature, as the difference between the final temperature and the initial temperature.
We have given,
c=4.18 j/g C
m=75 g
ΔT= 75 C-25 C=50 C
Substitute the values in the formula,
\(q=(75)(4.18)(50)\)
\(q=157 kJ\)
Therefore, The heat transferred is 157 kJ.