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Verified Answer :

we need to rationalize the denomenator

remember
(a+b)(a-b)=a²-b²
the bottom is the (a+b) form


mutliply it by \(\frac{ \sqrt{2}- \sqrt{10} }{\sqrt{2}- \sqrt{10}}\)
\((\frac{ \sqrt{2}- \sqrt{10} }{\sqrt{2}+ \sqrt{10}})(\frac{ \sqrt{2}- \sqrt{10} }{\sqrt{2}- \sqrt{10}})\)=
\(\frac{ (\sqrt{2}- \sqrt{10})^2 }{(\sqrt{2})^2- (\sqrt{10})^2}\)=
\(\frac{ 12-4\sqrt{5} }{2-10}\)=
\(\frac{ 12-4\sqrt{5} }{-8}\)=
\(\frac{ \sqrt{5}-3 }{2}\)