Answer:
The vertex of transformed parabola is:
(6,-3)
Step-by-step explanation:
We are given a equation of parabola as:
\(y=(x+1)^2+2\)
Now we have to transform the parabola
\(y=(x+1)^2+2\)
by shifting 7 units to the right and 5 units down.
We know that if a parabola is shifted 7 units to the right and 5 units to the down then the equation of the transformed parabola is given as:\(y=(x+1-7)^2+2-5\\\\y=(x-6)^2-3\)
We know that for any equation of parabola of the type:
\(y-k=(x-h)^2\)
The vertex of parabola is:
(h,k)
Now,the vertex of the transformed parabola is:
(6,-3)
