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Wan has 22 bulbs of the same shape and size in a box. The colors of and amounts of the bulbs are shown below: 6 blue bulbs 9 red bulbs 7 orange bulbs Without looking in the box, Wan takes out a bulb at random. He then replaces the bulb and takes out another bulb from the box. What is the probability that Wan takes out an orange bulb in both draws?

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Verified Answer :

VampireJellyfish

Probability of orange: 7/22
^ That's for one draw.
For 2 draws, it's when he draws an orange on one and then an orange on the next. So
7/22 x 7/22 = 49/484

Using it's concept, it is found that there is a 0.1012 = 10.12% probability that Wan takes out an orange bulb in both draws.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, in each of the two trials, there are 7 out of 22 orange bulbs, hence the probability is given by:

\(p = \left(\frac{7}{22}\right)^2 = 0.1012\)

More can be learned about probabilities at https://brainly.com/question/14398287

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