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Use substitution to solve.


2x² = 5 + y

4y = -20 + 8x²

Solve the first equation for y and substitute it into the second equation. The resulting equation is

Verified Answer :

konrad509

\(2x^2= 5 + y\\ 4y = -20 + 8x^2 \\\\ y=2x^2-5\\ 4y = -20 + 8x^2 \\\\ 4(2x^2-5)=-20+8x^2\\ 8x^2-20=8x^2-20\\ 0=0\)

The equations are identical. They're satisfied by any pair \((x,2x^2-5)\) where \(x\in\mathbb{R}\).

mommiesnootnoot

Answer:

Solve the first equation for y and substitute it into the second equation. The resulting equation is

✔ 8x² - 20 = -20 + 8x²

.

The system has

✔ infinitely many solutions

.

Step-by-step explanation:

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