y=a(x-h)²+k
vertex is (h,k)
and when a is positive then the parabola opens up and the vertex is lowest point
so since vertex is (13,-2) then it is below the x axis (-2<0)
and since a is negative, it opens down
so the vertex is the highest point
since the highest point is already below the x axis, there cannot be any x intercepts
0 intercepts
answer is C
