Answer:
\(7.5m/s\)
Explanation:
We use the formula to find the final velocity for the movement with constant acceleration:
\(V_{f}=V_{i}+at\)
where
\(V_{f}\) is the final velocity of the train
\(V_{i}\) is the initial velocity of the train, since it starts from rest \(V_{i}=0\)
\(a\) is the acceleration, \(a=1.5m/s^2\)
and \(t\) is the interval of time, \(t=5s\)
So, replacing the values in the formula we get:
\(V_{f}=0+(1.5m/s^2)(5s)\)
\(V_{f}=7.5m/s\)
The final velocity of the train is \(7.5m/s\)
