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A circle is drawn within a square as shown. What is the best approximation for the area of the shaded region? Use 3.14 to approximate pi. 10.54 cm² 27.02 cm² 87.47 cm² 104.86 cm² Circle inscribed inside a square with outside shaded, one side labeled 7 cm

Verified Answer :

Answer:

The best approximation for the area of the shaded region is \(10.54\ cm^{2}\)

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the square minus the area of the circle

Step 1

Find the area of the square

The area of the square is equal to

\(A=b^{2}\)

where

b is the length side of the square

we have

\(b=7\ cm\)

substitute

\(A=7^{2}=49\ cm^{2}\)

Step 2

Find the area of circle

The area of the circle is equal to

\(A=\pi r^{2}\)

we have

\(r=7/2=3.5\ cm\) -----> the radius is half the diameter

substitute

\(A=(3.14)(3.5^{2})=38.465\ cm^{2}\)

Step 3

Find the area of the shaded region

\(49\ cm^{2}-38.465\ cm^{2}=10.535\ cm^{2}\)


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The area of the shaded region is 10.54 cm square

Given-

The side of the square is 7 cm.

Let the shaded area be x m square and a is the length of the square.

A circle is inside the square.

To find out the shaded region, The area of the circle has to subtract from the area of the square.

Area of shaded region:

Shaded area(x) = area of square - area of circle

\(x=a^2-\pi \times\dfrac{d^2}{4}\)

Now, as the circle is perfectly drawn inside the square touching from four points of the square.

Therefore, the diameter will be equal to the side of the square which is a.

\(x=a^2-\pi \times\dfrac{a^2}{4}\)

\(x=7^2-3.14\times\dfrac{7^2}{4}\)

\(x=49-3.14\times\dfrac{49}{4}\)

\(x=49-38.465\)\(x=10.54\)

Hence, the area of the shaded region is 10.54 cm square.

For more about the square follow the link below-

https://brainly.com/question/11833983