The standard form of this equation is
\(y=\frac{1}{3}x+2\)
The slope of two parallel lines i the same, so the slope of the line we're looking for is also \(\frac{1}{3}\)
Since the line passes through \((-3,4)\), the equation is:
\((y-4)=\frac{1}{3}(x+3)\)
\(\boxed{y=\frac{1}{3}x+5}\)
