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MissPhiladelphia

To determine the amount of oxygen atoms in the compound given, we need convert it in terms of moles and relate the number of atoms O per mole of the compound. From there, we use the avogadro's number to convert it into atoms.

29.34 g Na2SO4 ( 1 mol / 142.04 g ) ( 4 mol O / 1 mol Na2SO4 ) (6.022x10^23 atoms O / 1 mol ) ) = 4.98x10^23 atoms O

Answer: The number of oxygen atoms in given mass of sodium sulfate are \(4.96\times 10^{23}\)

Explanation:

To calculate the number of atoms, we first need to find the number of moles of sodium sulfate. the equation used will be:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\)

Molar mass of sodium sulfate  142g/mol

Given mass of sodium sulfate = 29.34g

Putting values in above equation, we get:

\(\text{Moles of }Na_2SO_4=\frac{29.34g}{142g/mol}=0.206mol\)

In 1 mole of sodium sulfate, 4 moles of oxygen atoms are present.

Number of oxygen atoms present in 1 mole of sodium sulfate will be \(4\times 6.022\times 10^{23}\)

So, in 0.206 mol of sodium sulfate, the number of oxygen atoms will be = \(0.206\times 4\times 6.022\times 10^{23}=4.96\times 10^{23}\)

Hence, the number of oxygen atoms in given mass of sodium sulfate are \(4.96\times 10^{23}\)

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