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The amount of daily time that teenagers spend on a brand A cell phone is normally distributed with a given mean of 2.5 hr and standard deviation of 0.6 hr. What percentage of the teenagers spend more than 3.1 hr?


5%

10%

16%

32%

Verified Answer :

taskmasters

first the 3.1 hr is one standard deviation away from the mean:
2.5 + 0.6 = 3.1 hr. then the one standard deviation away from the mean contains 68% of the total population. so the percent that is higher from 3.1 hr is
% higher 3.1 hr = ( 100 - 68) / 2
% higher 3.1 hr = 32 / 2
% higher 3.1 hr = 16 %

C. 16%

In short, the correct selection would be answer 16%

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