Answer:
The correct option is 4.
Step-by-step explanation:
The possible ways of selecting r items from n items is defined as
\(^nC_r=\frac{n!}{r!(n-r)!}\)
Ping can choose 1 of 3 pasta meals, 1 of 7 chicken meals, or 1 of 3 fish meals. The number of ways ping can choose a dinner meal is
\(^3C_1\times ^7C_1\times ^3C_1=3\times 7\times 3=63\)
Therefore the number of ways ping can choose a dinner meal is 63.
Thus correct option is 4.
