Find two numbers whose sum is 24 and whose product is 63.
The numbers you are looking for are 3 and 21
21×3=63
And 21+3=24
The two numbers are 3 and 21.
Given that,
Based on the above information, the calculation is as follows:
x + y = 24
x = 24 - y
\(x \times y = 63\)
Now put the x value in the above equation
\((24 -y) \times y = 63\)
\(24y - y^2 = 63\)
\(y^2 - 24y - 63 = 0\)
\(y^2 - 21y - 3y - 63 = 0\)
y(y - 21) -3(y - 21)
It can be 3 and 21
Therefore the two numbers is 3 and 21
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