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loreenfernandez
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(high points) How can 1/4x - 3 = 1/2x + 8 be set up as a system of equations?

A4y + 4x = -12

2y + 2x = 16

B4y - x = -12

2y - x = 16

C4y + x = -12

2y + x = 16

D4y - 4x = -12

2y - 2x = 16

Verified Answer :

We can start with

y = (1/4)x - 3
y = (1/2)x + 8

Now multiply both sides of the first equation by 4, then multiply both sides of the second equation by 2. What do you get afterwards? = 14

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