Answer:
The value of (f+g)(x) is \(4x^2+\frac{9x}{4}-7\).
Step-by-step explanation:
The given functions are
\(f(x)=\frac{x}{4}-3\)
\(g(x)=4x^2+2x-4\)
We have to find the value of (f+g)(x).
\((f+g)(x)=f(x)+g(x)\)
\((f+g)(x)=\frac{x}{4}-3+4x^2+2x-4\)
Combine like terms.
\((f+g)(x)=4x^2+(\frac{x}{4}+2x)+(-3-4)\)
\((f+g)(x)=4x^2+\frac{x+8x}{4}+(-7)\)
\((f+g)(x)=4x^2+\frac{9x}{4}-7\)
Therefore the value of (f+g)(x) is \(4x^2+\frac{9x}{4}-7\).
