What is the GCF of 16s3t, 40s5, and 68t2?
deal with the numbers first
GCF of 16, 40 and 68 is 4
there is no GCF of the variables
so required GCF is 4
Answer:
4 is the GCF of \(16s^3t\), \(40s^5\) and \(68t^2\)
Step-by-step explanation:
Find the GCF of \(16s^3t\), \(40s^5\) and \(68t^2\).
GCF is the largest number that divide these numbers.
List the prime factor of \(16s^3t\), \(40s^5\) and \(68t^2\) as:
\(16s^3t = 2 \cdot 2 \cdot 2 \cdot 2 \cdot s \cdot s \cdot s \cdot t\)
\(40s^5 = 2 \cdot 2 \cdot 2 \cdot 5 \cdot s \cdot s \cdot s \cdot s \cdot s\)
\(68t^2 = 2 \cdot 2 \cdot 17 \cdot t \cdot t\)
Common factor of \(16s^3t\), \(40s^5\) and \(68t^2\) is, \(2 \cdot 2= 4\)
Greatest common factor of \(16s^3t\), \(40s^5\) and \(68t^2\) is, 4