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Alex invests $12,500 in a savings account that pays 2.75% interest compounded quarterly. how much money will he have in the account after 10 years?

Verified Answer :

Principle amount to be invested = 12500

Rate of interest = 2.75% or 0.0275

Interest is compounded quarterly so n= 4

Time = 10 years

Compound interest formula is : \(A=P(1+\frac{r}{n})^{nt}\)

Putting values in this formula we get,

A= \(12500(1+\frac{0.0275}{4} )^{4*10}\)

= \(12500(\frac{4+0.0275}{4})^{40}\)

= \(12500(1.006875)^{40}\)

= \(12500\times1.31529\)

= 16441.125

Hence, the account will have $16441.125 after 10 years.