apologiabiology apologiabiology

14-03-2017
Mathematics

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answer if you know the answer

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solve for x

\((3^{2x-1})(3^2)=(3x^{2+x})(3^x)\)

Verified Answer :

LammettHash LammettHash

17-03-2017

\(3^{2x-1}3^2=3^{2+x}3^x\)
\(3^{2x-1+2}=3^{2+x+x}\)
\(3^{2x+1}=3^{2x+2}\)

Because the bases are identical, so must be the exponents, meaning you have

\(2x+1=2x+2\)

but this has no solution.

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